CIRCLE:A circle is a collection of all points in a plane which are at a constant distance from a fixed point.
The fixed point is called the centre and the constant distance is known as the radius.
SECANT: A line which intersects a circle in two distinct points is called a secant of a circle.
TANGENT: A tangent to a circle is a line that intersects the circle in exactly one point.
THEORM 1: A tangent at any point of a circle is perpendicular to the radius through the point of contact.
Given:- A circle (O,r) and a tangent AB at point P.
To Prove:- OP┴ AB
Construction:- Take any point Q, other than P, on the tangent
AB. Join OQ. Suppose OQ meets the circle at R.
Proof:- Clearly, OP = OR
OQ = OR + RQ
OQ > OR
OQ > OP
OP < OQ
Thus, OP is the shorter distance than any other segment joining O to any point of AB.
Hence, OP ┴ AB
Length of tangent: The length of the segment of the tangent from the external point and the point of contact with the circle is called the length of the tangent.
THEORM 2: The lengths of tangents drawn from an external point to a circle are equal.
Given:- PQ and PR are two tangents from point P
to a circle (O,r)
To Prove:- AP = AQ
Construction:- Join OP, OQ and OA.
Proof:- By joining OP, OQ and OR,
angle OQP and ORP are right angles.
Now, in triangle OQP and ORP,
OQ = OR (radii of same circle)
OP = OP (Common)
OQP= ORP (RHS)
Therefore, PQ = PR ( by CPCT)
The fixed point is called the centre and the constant distance is known as the radius.
O is the centre and OA is the radius of the circle |
SECANT: A line which intersects a circle in two distinct points is called a secant of a circle.
Line PQ is a secant of a circle |
TANGENT: A tangent to a circle is a line that intersects the circle in exactly one point.
line PQ intersects a circle at a single point O, so it is tangent of a circle |
Given:- A circle (O,r) and a tangent AB at point P.
To Prove:- OP┴ AB
Construction:- Take any point Q, other than P, on the tangent
AB. Join OQ. Suppose OQ meets the circle at R.
Proof:- Clearly, OP = OR
OQ = OR + RQ
OQ > OR
OQ > OP
OP < OQ
Thus, OP is the shorter distance than any other segment joining O to any point of AB.
Hence, OP ┴ AB
Length of tangent: The length of the segment of the tangent from the external point and the point of contact with the circle is called the length of the tangent.
THEORM 2: The lengths of tangents drawn from an external point to a circle are equal.
Given:- PQ and PR are two tangents from point P
to a circle (O,r)
To Prove:- AP = AQ
Construction:- Join OP, OQ and OA.
Proof:- By joining OP, OQ and OR,
angle OQP and ORP are right angles.
Now, in triangle OQP and ORP,
OQ = OR (radii of same circle)
OP = OP (Common)
OQP= ORP (RHS)
Therefore, PQ = PR ( by CPCT)
i am having problem with one question...
ReplyDeleteIf the length of the arc of a sector of radius 5.6 cm is 17.2 cm. Then find the area of the sector.
From 100% success
@Raman please tell us the step where you are stuck and finding difficulty in sorting out...
DeleteWe can't provide straight away solution...
So please share your solution with us and tell us about particular step in which you are facing problem.
firstly i done like this-:
ReplyDeletewith the help of formula of length of arc i found the value of θ and put it in the formula of area of sector...
when i seen the answer's page , it is not correct....
It means you find the problem in calculation while solving the question....
ReplyDeletePlease tell us the value of Ѳ that you got after applying the formula of length of an arc ???
176
ReplyDelete@Raman as per our calculation we got the value of Ɵ = 172.8 and the area of sector = 65.50 .
DeleteBut you tell us what is the correct answer that is given in 100% success ?
answer is 16cm*cm
ReplyDeletebut i think Ɵ value comes 176....
As per our calculation ,if we take 172 as approx value of Ɵ then answer comes to be 23.54 .
DeleteBut if you are very confident with your answer then you should not go for the answer given in book because these reference books can sometimes be also wrong..