Q1. Find the probability that a leap year selected at random will contain 366 Sundays.
366 days = 52 weeks and 2 days.
therefore , leap year = 52 sundays.
the remaining two days can be :-
sunday and monday , monday and tuesday , tuesday and wednesday , wednesday and thursday ,
thursady and friday , friday and saturday , saturday and sunday.
total elementary events = 7 and favourable are 2
Therefore required probability = 2 / 7
Q2. Tickets numbered from 1 to 20 are mixed together . What is a probability that a ticket has
a number which is multiple of 3 or 7 ?
Here , total favourable outcomes = 3 , 6 , 7 , 9 , 12 , 14 , 15 and 18.
required probability = 8 / 20 = 2 / 5.
Q3. A bag contain 6oo pens out of which 12 are defective . What is probability for non - defective
pens ?
Total pens = 6oo
defective = 12
therefore , non - defective = 600 - 12 = 588
So , required probability = 588 / 600 = 49 / 50 = 0.98.
Q4. A letter is chosen at random from the letters of word 'ASSASSINATION' . Find the
probability that letter chosen is (i) vowel (ii) consonant.
Total letters = 13
(i) favourable for vowel = 6 (A , A , I , A , I , O )
SO , required probability = 6 / 13
(ii) probability for consonants = 1 - 6 / 13 = 7 / 13.
Q5. If x is chosen at random from the numbers -1 , 0 , 1 ,2 . What is a probability that x is
less than 2 ?
Total elementary outcomes = 5
favourable = 3 (-1 , 0 , 1)
So , required probability = 3 / 5.
Source :- R.D. Sharma and 100 % Success.
366 days = 52 weeks and 2 days.
therefore , leap year = 52 sundays.
the remaining two days can be :-
sunday and monday , monday and tuesday , tuesday and wednesday , wednesday and thursday ,
thursady and friday , friday and saturday , saturday and sunday.
total elementary events = 7 and favourable are 2
Therefore required probability = 2 / 7
Q2. Tickets numbered from 1 to 20 are mixed together . What is a probability that a ticket has
a number which is multiple of 3 or 7 ?
Here , total favourable outcomes = 3 , 6 , 7 , 9 , 12 , 14 , 15 and 18.
required probability = 8 / 20 = 2 / 5.
Q3. A bag contain 6oo pens out of which 12 are defective . What is probability for non - defective
pens ?
Total pens = 6oo
defective = 12
therefore , non - defective = 600 - 12 = 588
So , required probability = 588 / 600 = 49 / 50 = 0.98.
Q4. A letter is chosen at random from the letters of word 'ASSASSINATION' . Find the
probability that letter chosen is (i) vowel (ii) consonant.
Total letters = 13
(i) favourable for vowel = 6 (A , A , I , A , I , O )
SO , required probability = 6 / 13
(ii) probability for consonants = 1 - 6 / 13 = 7 / 13.
Q5. If x is chosen at random from the numbers -1 , 0 , 1 ,2 . What is a probability that x is
less than 2 ?
Total elementary outcomes = 5
favourable = 3 (-1 , 0 , 1)
So , required probability = 3 / 5.
Source :- R.D. Sharma and 100 % Success.
Feel free to ask about queries and clear your doubts !!!........
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