MATHS UNIT TEST
- Which of the following rational number have terminating decimal?
a. 16/225 b.
5/18 c. 2/21 d. 7/250
Ans: 7/250.
Since 7/250 = 7/53x2
3
- The H.C.F and L.C.M of two rational nos. are equal then the nos. must be
a. prime b.
co-prime c. composite d. equal
Ans: Equal
- Given that H.C.F (306,657) = 9. Find the L.C.M.
Ans: Since we know that H.C.F x L.C.M = a x b
9 x L.C.M = 306 x 657
L.C.M = (306 x 657)/9
= 22338.
- Express 3825 as the product of its prime factors.
Ans: 3825 = 5 x 5 x 3 x 3 x 17
= 52 x 32
x 17
- Find a quadratic polynomial if sum and product of its zeros are -1/4 and 1/4.
Ans: Equation for quadratic polynomial is
X2- (sum) x + product = 0
X2- (-1/4) x +
(1/4) = 0
X2 + 1/4x + ¼ = 0
- Use Euclid’s division algorithm to find the H.C.F of 210 and 55.
Ans: H.C.F of 210 and 55
210 = 55 x 3 + 45
55 = 45 x 1 + 10
45 = 10 x 4 + 5
10 = 5 x 2 + 0
So, H.C.F = 5.
- Prove that √3 is irrational number.
Ans: Let us consider √3 is rational = p/q = where p and q are
co-primes.
Squaring: (√3)2 = p2/q2
3 = p2/q2
q2 = p2/3
(1)
= 3 divides p2
= 3 divides p (2)
Let us suppose p=3p’
Inserting value of p in (1)
3q2 = (3p’)
q2 = 3p’
p2 = q2/3
= 3 divides p2
= 3 divides p
(3)
From (2) and (3)
3 divides p and q
= H.C.F of p and q is 3
But p and q are co-primes
= our supposition is wrong
= √3 is irrational.
- Show that any positive odd integer is of the form 4q+1 and 4q+3 where q is some integer.
Ans: Let a be any positive integer, b=4
Acc. To Euclid’s division algorithm
A=bq+r where 0_< r < b
R=0,1,2,3
When r = 0
A=bq+0
When r = 1
A=bq+1
When r = 2
A=bq+2
When r = 3
A=bq+3
So, the positive odd integer among
this is 4q+1 and 4q+3.
- Divide the polynomial p(x) = x4-3x2+4x+5 by the polynomial g(x) = x2+1-x. Find the ques. and rem.
Ans: p(x) = x4-3x2+4x+5
g(x) = x2+1-x = x2-x+1
Rem = 8, quest = x2+x-3.
- Obtain all other zeros of 3x4+6x3-2x2-10x-5 if two of it’s zeros are √5/3 and -√5/3.
Ans: p(x) = 3x4+6x3-2x2-10x-5
Given zero = (x-√5/3) (x+√5/3)
Product = (x2-5/3)
P(x) = (x2-5/3)(3x2+6x+3)
Now: 3x2+6x+3
3x2+3x+3x+3
3x(x+1)+3(x+1)
(3x+3)(x+1)
Now x = -1, -1 YOU ARE MOST WELCOME TO ASK ANY DOUBT
Thanks For Helping Out QUES 8, & 9 SOL.
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